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The distance between Akola and Bhusawal is 168 km. An express traintakes 1 hour less than a passenger train to cover the distance. Find theaverage speed of each train if the average speed of the express train ismore by 14 km/hr than the speed of the passenger train. |
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Answer» Let the speed of passenger train is x kmp and that of express train is y kmphDistance = 168 km Time taken by Express train to travel between akola to bhusawal = 168/y hour Time taken by passenger train to travel between akola to bhusawal = 168/x hour According to the question Express train taking 1 hour less168/y + 1 = 168/x168x + xy = 168y168x - 168y + xy = 0..........(1) ATQy = x + 14............(2)Substitute from eq 2168x - 168(x + 14) + x(x + 14) = 0168x - 168x - 2352 + x^2 + 14x = 0x^2 + 14x - 2352 = 0x^2 + 56x - 42x - 2352 = 0x(x + 56) - 42(x + 56) = 0(x + 56)(x - 42) = 0x = - 56, 42 negative value can be discarded. Thus Speed of passenger train 42 kmph Speed of express train = 42+14= 56 kmph |
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