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| 1. |
The distance between an object and its image produced by a converging lens is 0.72 m. The magnification is 2. What will be the magnification when the object is moved by 0.04 m towards the lens ? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a><br/>4<br/>3<br/>6</p>Solution :(b) Given, `m = 2` "and the <a href="https://interviewquestions.tuteehub.com/tag/image-11684" style="font-weight:bold;" target="_blank" title="Click to know more about IMAGE">IMAGE</a> formed is <a href="https://interviewquestions.tuteehub.com/tag/real-1178490" style="font-weight:bold;" target="_blank" title="Click to know more about REAL">REAL</a>" <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> "For a real image" (1)/(f) = (1)/(v) + (1)/(u)` <br/> `or "" 1 + (1)/(m) = (u)/(f)` <br/> `rArr "" 1+ (1)/(2) = (u)/(f)` <br/> `rArr (3)/(2) = (0.72)/(f)`<br/> `or "" f = (0.72 xx 2)/(3) = 0.16m` <br/> As the object is moved by 0.04 m towards the <a href="https://interviewquestions.tuteehub.com/tag/lens-1071845" style="font-weight:bold;" target="_blank" title="Click to know more about LENS">LENS</a>, the new <br/> `mu_(1) = 0.72 - 0.04 = 0.68 m` <br/> Again real image is formed <br/> `rArr "" 1 + (1)/(m) = (u_(1))/(f)` <br/> `rArr "" (1)/(m) = (0.04)/(0.16)` <br/> `rArr "" m = 4`.</body></html> | |