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    				| 1. | The distance between `H^(+) and Cl^(-)` ions in HCl molecules is `1.38Å.` The potential due to this dipole at a sistance of `10Å` on the axis of dipole isA. `2.1` VB. `1.8` VC. `0.2` VD. `1.2` V | 
| Answer» Correct Answer - C Here, `2a=1.38xx10^(-10)m, r=10xx10^(-10)` m charge , q=`1.6xx10^(-19)`C As potential , `V=P/(4piepsilon_0r^2)=(q(2a))/(4piepsilon_0r^2) = (9xx10^9xx1.6xx10^(-19)xx1.38xx10^(-10))/((10xx10^(-10))^2)` | |