The distance between plates of a parallel plate capacitor is `5d`. Let the positively charged plate is at `x=0` and negatively charged plate is at `x=5d`. Two slabs one fo conductor and other of a dielectric of equal thickness `d` are inserted between the plates as shown in figure. Potential verus distance graph will look like: A. B. C. D.

The distance between plates of a parallel plate capacitor is `5d`. Let

1.	The distance between plates of a parallel plate capacitor is `5d`. Let the positively charged plate is at `x=0` and negatively charged plate is at `x=5d`. Two slabs one fo conductor and other of a dielectric of equal thickness `d` are inserted between the plates as shown in figure. Potential verus distance graph will look like: A. B. C. D.
Answer» Correct Answer - 2 `V_(1)-V_(2)=kq((1)/(r_(1))-(1)/(r_(2)))` `r_(2)-r_(1)=((V_(1)-V_(2))r_(1)r_(2))/(kq)`, but (r_(2)-r_(1))=t` `:.ralpha_(1)r_(2)` If P.D is constant then `(r_(2)-r_(1))=t`

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