The distance between the inner and outer wheels of a car is 1.75 m and its centre of gravity is 0-50 m above the ground. What is the maximum speed with which the car can negotiate a curve of radius of 40 m without overturning ?

The distance between the inner and outer wheels of a car is 1.75 m and

1.	The distance between the inner and outer wheels of a car is 1.75 m and its centre of gravity is 0-50 m above the ground. What is the maximum speed with which the car can negotiate a curve of radius of 40 m without overturning ?
Answer» Solution : Distance between the inner and outer wheels of CAR = 2s = 1 -75 m Height of the C.G of the car from the ground = `h=0.5 m` Maximum SPEED = `v_("MAX") = ?` RADIUS of the circular road = r= 40 m `v_("max") = sqrt((gsr)/h) = sqrt((9.8 xx 0.875 xx 40)/0.5)` = 26.2 m/s