The distance between the inner and outer wheels of a car is 1.75 m and its centre of gravity is 0-50 m above the ground. What is the maximum speed with which the car can negotiate a curve of radius of 40 m without overturning ?

The distance between the inner and outer wheels of a car is 1.75 m and

1.	The distance between the inner and outer wheels of a car is 1.75 m and its centre of gravity is 0-50 m above the ground. What is the maximum speed with which the car can negotiate a curve of radius of 40 m without overturning ?
Answer» <html><body><p></p>Solution : Distance between the inner and outer wheels of <a href="https://interviewquestions.tuteehub.com/tag/car-909011" style="font-weight:bold;" target="_blank" title="Click to know more about CAR">CAR</a> = 2s = 1 -<a href="https://interviewquestions.tuteehub.com/tag/75-334971" style="font-weight:bold;" target="_blank" title="Click to know more about 75">75</a> m <br/>Height of the C.G of the car from the ground = `h=0.5 m` <br/> Maximum <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> = `v_("<a href="https://interviewquestions.tuteehub.com/tag/max-546895" style="font-weight:bold;" target="_blank" title="Click to know more about MAX">MAX</a>") = ?` <br/> <a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> of the circular road = r= 40 m <br/> `v_("max") = sqrt((gsr)/h) = sqrt((9.8 xx 0.875 xx 40)/0.5)` <br/> = 26.2 m/s</body></html>