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The distance between the planes 2x+3y+4z=4 and 4x+6y+8z=12 is (a) 2√29 units (b) 10√29 units (c) 4 units (d) 2 units |
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Answer» The distance between the planes 2x+3y+4z=4 and 4x+6y+8z=12 is (a) 2√29 units (b) 10√29 units (c) 4 units (d) 2 units |
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