InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The distance of the point (1,-5,9) from the plane x-y+z = 5 measured along the line x = y = z isA. `5sqrt(3)`B. `3sqrt(10)`C. `3sqrt(5)`D. `10sqrt(3)` |
|
Answer» Correct Answer - D The equation of the line pasing through the point `A(1,-5,9)` and parallel to the line `x=y=z` is `(x-1)/1=(y+5)/1=(z-9)/1` Suppose it cuts the plane `x-y+z=5` at `P(lamda+1,lamda-5,lamda+9)` As `P` lies on `x+y+z=5` `:. lamda+1-lamda+5+lamda+9=5implieslamda=-10.` So, the coordinates of `P` are `(-9,-15,-1)`. Hence, required distance `-AP-sqrt(100+100+100)=10sqrt(3)` |
|