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The distance of the point P(1,2,3) from the line which passes through the point (4,2,2) and parallel to the vector `2hati+3hatj+6hatk` isA. `sqrt10`B. `sqrt7`C. `sqrt5`D. 1 |
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Answer» Correct Answer - A The equation of the of line which passess through the point `A (4,2,2)` and parallel to the vector `2hati + 3hatj + 6hatk` is `(x-4)/(2) = (y -2)/(3) = (x-2)/(6)` Distance of point `P(1,2,3)` form the line `sqrt((1-4)^(2) +(2-2)^(2) (3-2)^(2) - {2(1-4)+3(2-2) +6(3-2)^(2)})` ` = sqrt(9+0+1-(-6 + 0 + 6)^(2)) = sqrt(10)` |
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