The distance travelled by a particle in time t is given by s=(2.5)t^(2).find (A)the average speed of the particle during the time 0 to 5.0s, and (B) the instantaneous speed at t=5.0s Here s is in metres.

The distance travelled by a particle in time t is given by s=(2.5)t^(2

1.	The distance travelled by a particle in time t is given by s=(2.5)t^(2).find (A)the average speed of the particle during the time 0 to 5.0s, and (B) the instantaneous speed at t=5.0s Here s is in metres.
Answer» Solution :The distance TRAVELLED during tiem `0"to"5.0s` is `=(2.5)(5.0)^(2)=62.5m.` the average SPEED during this TIME is `v_(av)=(62.5m)/(5s)=12.5m//s` `s=(2.5)t^(2)"or"(ds)/(dt)=(2.5)(2t)=(5.0)t` At `t=5.0s "the speed is" v=(ds)/(dt)=(5.0)(5.0)=25m//s`