1.

The distance travelled by a particle in time ’t’ is given by s = (2.5 m/s2) t2. Find the average speed of the particle during the time ‘O’ to ‘5’ sec.

Answer»

The distance travelled by the particle from 0 to 5 sec is s = 2.5 m/s2 × 52 = 62.5 m

Average speed during this time v=\(\frac{s}t\)=\(\frac{62.5}5\)=12.5 m/sec.



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