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The distance traversed by a particle moving along a straight lne is given by `x = 180t+50t^(2)` metre. The acceleration of the particle isA. `180 ms^(-2)`B. `580 ms^(-2)`C. `100 ms^(-2)`D. `50 ms^(-2)` |
Answer» Correct Answer - C `x=180t+50t^(2)` `upsilon=(dx)/(dt)=180+100t` `a=(d upsilon)/(dt)=100m//s^(2)` |
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