1.

The distance traversed by a particle moving along a straight lne is given by `x = 180t+50t^(2)` metre. The acceleration of the particle isA. `180 ms^(-2)`B. `580 ms^(-2)`C. `100 ms^(-2)`D. `50 ms^(-2)`

Answer» Correct Answer - C
`x=180t+50t^(2)`
`upsilon=(dx)/(dt)=180+100t`
`a=(d upsilon)/(dt)=100m//s^(2)`


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