InterviewSolution
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InterviewSolution
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The distance (x) particle moving in one dismension, under the action of a constant force is related to time (t) by equation `tsqrt x +3` where (x) is in vettres and (t) in seconds. Find the displacement of the particle when its velcity is zero. |
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Answer» Given, `t= sqrt x+ 3 or sqrt x = t -3 ` Squaring both the sides, we get ` x=(t-3) ^(2) =t^(2) -6 t +9` Diferntiating it w.r.t. time (t) we get velocity, ` v=(dx)/(dt) =2 t-6` when `v=0` , then `2 t -6 =0 or t=3 second`. At ` t=3 `, distplacement is given by, ` x=t^(2) -6 t+ 9 = 3^(2) -6 xx 3+=0`. Hence, displacement of the particle is zero when its velocity is zero. |
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