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The distances of a point on the screen from two slits in biprism experiment is `1.8xx10^(-5)` m and `1.23xx10^(-5)` m if wavelength of light used is 6000 Å then fringe formed at that point isA. `8^(th)` darkB. `9^(th)` darkC. `10^(th)` darkD. `11^(th)` dark |
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Answer» Correct Answer - C Path diff. `=1.8xx10^(-5)-1.23xx10^(-5)` `=0.57xx10^(-5) m` Now, `n= ("Path diff.")/("Wavelength")= (0.57xx10^(-5))/(6xx10^(-7))=9.5` Thus, given, point is `10^(th)` dark point. |
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