The distribution of electrons among molecular orbitals is called the electronic configuration of the molecule which provides us the following very important informations about the molecule. (A)Stability of molecule : The molecule is stable if number of bonding moleculer orbital electrons `(N_b)` is greater than the number of antibonding molecular orbital electrons `(N_a)`. (B) Bond order : Bond order `=1/2(N_b-N_a)` A positive bond order means a stable molecule while a negative or zero bond order means an unstable molecule. ( C)Nature of the bond : Bond order 1,2 and 3 corresponds to single , double and triple bonds respectively. (D)Bond length: Bond length decreases as bond order increases. (E)Magnetic nature: Molecular orbitals in a molecule are doubly occupied , the substance is diamagnetic and if one or more molecular orbitals are singly occupied, it is paramagnetic. Which of the following statements is incorrect ?A. Among `O_2^(+),O_2` and `O_2^(-)` the bond length decreases as `O_2^(-) gt O_2 gt O_2^(+)`B. `He_2` molecule does not exist as the bonding and anti-bonding orbitals cancel each otherC. `C_2, O_2^(2+)` and `Li_2` are dimagneticD. In `F_2` molecule the energy of `sigma_(2p_z)` is more than `pi_2p_x` and `pi_2p_y`

The distribution of electrons among molecular orbitals is called the e

1.	The distribution of electrons among molecular orbitals is called the electronic configuration of the molecule which provides us the following very important informations about the molecule. (A)Stability of molecule : The molecule is stable if number of bonding moleculer orbital electrons `(N_b)` is greater than the number of antibonding molecular orbital electrons `(N_a)`. (B) Bond order : Bond order `=1/2(N_b-N_a)` A positive bond order means a stable molecule while a negative or zero bond order means an unstable molecule. ( C)Nature of the bond : Bond order 1,2 and 3 corresponds to single , double and triple bonds respectively. (D)Bond length: Bond length decreases as bond order increases. (E)Magnetic nature: Molecular orbitals in a molecule are doubly occupied , the substance is diamagnetic and if one or more molecular orbitals are singly occupied, it is paramagnetic. Which of the following statements is incorrect ?A. Among `O_2^(+),O_2` and `O_2^(-)` the bond length decreases as `O_2^(-) gt O_2 gt O_2^(+)`B. `He_2` molecule does not exist as the bonding and anti-bonding orbitals cancel each otherC. `C_2, O_2^(2+)` and `Li_2` are dimagneticD. In `F_2` molecule the energy of `sigma_(2p_z)` is more than `pi_2p_x` and `pi_2p_y`
Answer» Correct Answer - D (A)Bond order `prop 1/("bond length")` Bond order `O_2^+=2.5, O_2=2 O_2^(-)=1.5` so correct order of bond length is `O_2^(-) gt O_2 gt O_2^+` (B)Bond order for `He_2=(2-2)/2=0` So `He_2` does not exist. (C )In all these molecules all electrons all electrons are paired in molecular orbitals. So they are all diamagnetic (D)`F_2`MOT configuration : `sigma1s^2sigma^1s^2sigma2s^2sigma^2s^2sigma2p_z^2pi2p_y^2pi2p_z^2pi^2p_y^2pi^2p_z^2pi^2p_z^2sigma^2p_z^@`

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