The distributive law from algebra states that for all real numbers, c,

1.	The distributive law from algebra states that for all real numbers, c, a1 and a2, we have c(a1+a2)=ca1+ca2. Use this law and mathematical induction to prove that, for all natural numbers, n≥2, if c, a1,a2,.....an are any numbers, then c(a1+a2+....+an)=ca1+ca2+......+can.
Answer» The distributive law from algebra states that for all real numbers, c, $a_{1} a n d a_{2}$ , we have $c (a_{1} + a_{2}) = c a_{1} + c a_{2}$ . Use this law and mathematical induction to prove that, for all natural numbers, $n \geq 2$ , if c, $a_{1}, a_{2}, . . . . . a_{n}$ are any numbers, then $c (a_{1} + a_{2} + . . . . + a_{n}) = c a_{1} + c a_{2} + . . . . . . + c a_{n}$ .

The distributive law from algebra states that for all real numbers, c, a1 and a2, we have c(a1+a2)=ca1+ca2. Use this law and mathematical induction to prove that, for all natural numbers, n≥2, if c, a1,a2,.....an are any numbers, then c(a1+a2+....+an)=ca1+ca2+......+can.

Answer»

The distributive law from algebra states that for all real numbers, c, $a_{1} a n d a_{2}$ , we have $c (a_{1} + a_{2}) = c a_{1} + c a_{2}$ .

Use this law and mathematical induction to prove that, for all natural numbers, $n \geq 2$ , if c, $a_{1}, a_{2}, . . . . . a_{n}$ are any numbers, then

$c (a_{1} + a_{2} + . . . . + a_{n}) = c a_{1} + c a_{2} + . . . . . . + c a_{n}$ .

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The distributive law from algebra states that for all real numbers, c, a1 and a2, we have c(a1+a2)=ca1+ca2. Use this law and mathematical induction to prove that, for all natural numbers, n≥2, if c, a1,a2,.....an are any numbers, then c(a1+a2+....+an)=ca1+ca2+......+can.

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