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The doctor took the temperature of a dead body at11.30 Pm which was `94. 6^0Fdot`He took the temperature of the body again afterone hour, which was `93. 4^0Fdot`If the temperature of the room was`70^0F`, estimate the time of death. Taking normaltemperature of human body as `98. 6^0Fdot`[Given: `log(143)/(123)=0. 15066 ,log(123)/(117)=0. 05`]A. 8.30 a.m.B. 8.30 p.m.C. 2.30 a.m.D. 9.30 p.m.

Answer» Correct Answer - B


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