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The domain of the function defined by f(x) = sin-1 √(x - 1) is …(a) [1, 2] (b) [-1, 1] (c) [0, 1] (d) [-1, 0] |
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Answer» (a) [1, 2] The domain for sin-1 x is [0, 1] So, √(x - 1) = 0 ⇒ x – 1 = 0 ⇒ x = 1 √(x - 1) = 1 ⇒ x – 1 = 0 ⇒ x = 2 ∴ The domain is [1, 2] |
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