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The domain of the function \(f(x) = (\sqrt{x})^2\) is (a) – ∞ < x < ∞ (b) 0 < x < ∞ (c) 0 ≤ x < ∞ (d) None of these |
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Answer» Answer : (c) = 0 ≤ x < ∞ Since \(\sqrt{x}\) is defined for only non-negative real numbers, therefore domain of f (x) = (\(\sqrt{x}\))2 is [0, ∞). |
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