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The drain cleaner Drainex contains small bits of aluminimum which react with caustic soda to form hydrogen. What volume of hydrogen at `20^(@)C` and `1 "bar"` will be released when `0.15 g` of aluminimum reacts? |
Answer» The chemical reaction taking place is `underset(2xx27 g)underset(2 mol)(2AI)+2NaOH+2H_(2)O rarr 2NaAIO_(2)+underset(3mol)(3H_(2)` `54 g` of `Al` produces hydrogen `=3 mol` `0.15 g` of `Al` produces hydrogen `=(3xx0.15)/(54) mol=8.33xx10^(-3)mol` Calculation of volume of `8.33xx10^(-3)mol` of hydrogen at `20^(@)C` and `1` bar: `V=(nRT)/(P)` `=(8.33xx10^(-3)(mol)xx0.083("bar" L K^(-1) mol^(-1))xx293 (K))/(1 "bar")` `=0.20282 L=202.82 mL` |
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