the driver of a three wheeler moving with aspeed of 36 km/h sees a chi

1.	the driver of a three wheeler moving with aspeed of 36 km/h sees a child standing in the middle of the road and bring his vehicle to rest in 4.0s just in time to save the child . what is the average retarding force on the vehicle ? the mass of the three wheeler is 400kg and the mass of the driver is 60 kg
Answer» ==============ⓢⓦⓘⓖⓨ $\bold\red{hello...frd\:swigy\:here}$ ==============ⓢⓦⓘⓖⓨ U = 36 km/h V = 10 m/s t = 4 s Mass of three- wheeler, m = 400 kg Mass of the driver, m' = 65 kg Total mass of the system, M = 400 + 65 = 465 kg ▪Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as: v = u + at => a= v- u / t = (0-10)/4 = -2.5 m/s^2 ◾The NEGATIVE sign indicates that the velocity of the three-wheeler is decreasing with time. ◾Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as: F = Ma = 465 × (–2.5) = –1162.5 N ◾The negative sign indicates that the force is acting against the direction of motion of the three-wheeler. I hope, this will HELP you___❤❤ ======================= ·.¸¸.·♩♪♫ ⓢⓦⓘⓖⓨ ♫♪♩·.¸¸.· ___________♦♦⭐♦ ♦___________

the driver of a three wheeler moving with aspeed of 36 km/h sees a child standing in the middle of the road and bring his vehicle to rest in 4.0s just in time to save the child . what is the average retarding force on the vehicle ? the mass of the three wheeler is 400kg and the mass of the driver is 60 kg

Answer»

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$\bold\red{hello...frd\:swigy\:here}$

==============ⓢⓦⓘⓖⓨ

U = 36 km/h

V = 10 m/s

t = 4 s

Mass of three- wheeler, m = 400 kg

Mass of the driver, m' = 65 kg

Total mass of the system, M = 400 + 65 = 465 kg

▪Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:

v = u + at

=> a= v- u / t = (0-10)/4 = -2.5 m/s^2

◾The NEGATIVE sign indicates that the velocity of the three-wheeler is decreasing with time.

◾Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as:

F = Ma = 465 × (–2.5) = –1162.5 N

◾The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.

I hope, this will HELP you___❤❤

=======================

·.¸¸.·♩♪♫ ⓢⓦⓘⓖⓨ ♫♪♩·.¸¸.·

___________♦♦⭐♦ ♦___________