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The DRs of the line 3x + 1 = 6y − 2 = 1 − z are (a) (1/3,6,-1)(b) (3,1/6,-1)(c) (1/3,1/6,-1)(d) (1/3,-1/6,1) |
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Answer» Correct option is (c) (1/3,1/6,-1) Explantion : We have 3x + 1 = 6y - 2 = 1 - z (x + (1/3))/ (1/3) = (y - (1/3))/ (1/6) = (z - 1)/ -1 Therefore, the DRs are (1/3,1/6,-1) |
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