The e.m.f of a Daniell cell at 298 K is E(0.01 M) (1.0M)When that conc

1.	The e.m.f of a Daniell cell at 298 K is E(0.01 M) (1.0M)When that concentration of ZnSO4 is 1.0 M andthat of CuSO4 is 0.01 M, the e.m.f changed toE2. What is the relationship between E1 and E[AIPMT-2003]
Answer» For E1 = Eocell – (0.0529/2)log(Zn2+/Cu2+) => Eocell – (1.5)(0.0529)........(1) For E2 = Eocell – (0.059)..............(2) Substract the eqns. (1) and (2) we get, E1 – E2 = 0.059*2.5 = > 0.13225 VOLT

The e.m.f of a Daniell cell at 298 K is E(0.01 M) (1.0M)When that concentration of ZnSO4 is 1.0 M andthat of CuSO4 is 0.01 M, the e.m.f changed toE2. What is the relationship between E1 and E[AIPMT-2003]

Answer»

For E1 = Eocell – (0.0529/2)log(Zn2+/Cu2+) => Eocell – (1.5)(0.0529)........(1)

For E2 = Eocell – (0.059)..............(2)

Substract the eqns. (1) and (2) we get,

E1 – E2 = 0.059*2.5 = > 0.13225 VOLT