InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The `E^(@)` values for the changes given below are measured againest `NHE` at `27^(@)C`. `Cu^(2+) + e rarr Cu^(+), E^(@) = + 0.15 V`, `Cu^(+) + e rarr Cu, E^(@) = + 0.50 V`, `Zn^(2+) + 2e rarr Zn, E^(@) = - 0.76 V` The temperature coefficient of emf a cell designed as `Zn"|"underset(1 M)(Zn^(2+))"||"underset(0.1 M)(Cu^(2+))"|"Cu` is `-1.4 xx 10^(-4)V` per degree. For a cell reaction in equilibrium `DeltaG = 0` and `DeltaG^(@) = -2.303 RTlog_(10)K_(c)`. The heat of reaction and entropy change during the reaction are are related by `DeltaG = DeltaH - TDeltaS`. The heat of reaction for the change `Zn+underset(0.1 M)(Cu^(2+)) hArr underset(1M)(Zn^(2+))+Cu` at `27^(@)C` is :A. `-2118 xx 10^(5)J`B. `-2.197 xx 10^(5)J`C. `-2.237 xx 10^(5)J`D. `-1.818 xx 10^(5)J` |
|
Answer» Correct Answer - A `DeltaH = nF[T((deltaE)/(deltaT))_(P)-E]` `= 2 xx 96500[300 xx (-1.4 xx 10^(-4)) -1.0555]` `= -02.118 xx 10^(5)J` |
|