1.

The earth is assumed to be a sphere of radius R. A platform is arranged at a height R from the surface of the earth. The escape velocity of a body from this platform is fu, where v is its escape velocity from the surface of the earth the value of f is ..........

Answer»

`1/sqrt2`
`1/3`
`1/2`
`sqrt2`

Solution :`implies` Potential energy at HEIGHT `R = - (GMM)/(2R)`
If a body of MASS m isprojected at height R from the surface of earth with the velocity `v_e` so that it goes beyond the earth.s gravitational field and escape from earth then ,
`1/2 mv_e^2 =(GM)/(2R) .m`
`:. v_e = sqrt((GM)/R) " or " v_e = sqrt(gR)`
Now `,v = sqrt(2gR) ` for `v = sqrt2 v_e ` or `v_e =1/sqrt2 v`
`:. f =1/sqrt 2`


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