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The eccentricity of the ellipse (x – 3)2 + (y – 4)2 = (y2/9) is …(a) √3/2(b) 1/3(c) 1/3√2(d) 1/√3 |
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Answer» (b) 1/3 The given equation is of the form FP2 = e2PM2 i.e., (x – 3)2 + (y – 4)2 = (1/9)y2 e2 = 1/9 e = 1/3 |
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