1.

The eccentricity of the hyperbola `9x^(2)-16y^(2)+72x-32y-16=0`, isA. `(5)/(4)`B. `(4)/(5)`C. `(9)/(16)`D. `(16)/(9)`

Answer» We have,
`9(x^(2)+8x)-16(y^(2)-2y)=16`
`implies9(x+4)^(2)-16(y+1)^(2)=144`
`implies((x+4)^(2))/(16)-((y+1)^(2))/(9)=1`
Here, `a^(2)=16` and `b^(2)=9`.
`:.e^(2)=1+(b^(2))/(a^(2))=1+(9)/(16)=(25)/(16)impliese=(5)/(4)`


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