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The eccentricity of the hyperbola `9x^(2)-16y^(2)+72x-32y-16=0`, isA. `(5)/(4)`B. `(4)/(5)`C. `(9)/(16)`D. `(16)/(9)` |
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Answer» We have, `9(x^(2)+8x)-16(y^(2)-2y)=16` `implies9(x+4)^(2)-16(y+1)^(2)=144` `implies((x+4)^(2))/(16)-((y+1)^(2))/(9)=1` Here, `a^(2)=16` and `b^(2)=9`. `:.e^(2)=1+(b^(2))/(a^(2))=1+(9)/(16)=(25)/(16)impliese=(5)/(4)` |
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