1.

The E° for Cl-/Cl2 is 1.36, for I-/I2 is +0.53, for Ag+/Ag is + 0.79, Na+ is -2.71 and for Li+/Li is -3.04 V Arrange the following species in decreasing order of reducing strength. I-, Ag, Cl-, Li, Na.

Answer»

The more negative or less positive is the electrode potential, more is the reducing strength of the species. Since the electrode potentials increases in the order: 

Li(-3.04V) < Na(-2.7V) < I-(0.53 V) < Ag(+0.79V) < Cl- (+1.36V), 

therefore, the reducing strength decreases in the order 

Li > Na > I- > Ag > Cl-


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