1.

The edge length of a face-centred cubic unit cell is `508 pm`. If the radius of the cation is `110 pm` the radius of the anion isA. `144`pmB. `288` pmC. `618` pmD. `398` pm

Answer» Correct Answer - A
For face-centred cubic unit cell (e.g., that of `NaCl`), edge length `= 2 xx` (Distance between cation and anion `= 2 (r_(c) + r_(a)) = 508 "pm"` (given). Putting `r_(c) = 110 "pm"`, we get `r_(a) = 144 "pm"`.


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