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The edge length of the unit cell of NaCl crystal lattice is 552 pm. If ionic radius of sodium ion is 95 pm, what is the ionic radius of chloride ion?(A) 190pm(B) 368pm(C) 181pm(D) 276pm |
Answer» Correct answer is: (C) 181pm 2r+ + 2r– = 552; r+ + r– = \(\cfrac{552}{2}\)= 276 r– = 276 – 95 = 181 pm. |
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