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The efficiency of a carnot engine eta = 1/10. This carnot engine used as refrigerator. If work done on system is 10 J, then heat absorbed from sink will be …….

Answer»

100 J
99 J
90 J
1 J

SOLUTION :Efficiency of carnot engine
`ETA=(T_1-T_2)/T_1=(Q_1-Q_2)/Q_1`
COEFFICIENT of performance of refrigerator ,
`beta=Q_2/(Q_1-Q_2)`
`beta=(1-eta)/eta`
`therefore beta=(1-1/10)/(1/10)=(9/10)/(1/10)=9`
but `beta=Q_2/W`
`therefore Q_2=betaW`
`therefore Q_2=9xx10=90` J


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