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| 1. |
The efficiency of a carnot engine is 40%, whose sink is at a temperature of 300 K. By how much should be temperature of the source be increased be get an efficiency of 60% ? |
| Answer» Solution :`0.4 =1 - (300 //T_(1)) , T _(1) = 500 K, 0.6 = 1 - (300 // T _(1)) , T_(1) = 750K,` INCREASE by 250 K | |