1.

The efficiency of carnot engine working between temperatures 200^@ C and 0^@ C is eta_1. The efficiency of this engine is eta_2 when it work between temperatures 0^@ C and -200^@ C. Then eta_1/eta_2=_____

Answer»

`1.0`
`0.721`
`0.577`
`0.34`

SOLUTION :`T_1`=200+273 =473 K
`T_2`=0+273=273 K
`T._1`=0+273 =273 K
`T._2`=-200+273 =73 K
`eta_1=200/473`
`eta_2=200/273`
`therefore eta_1/eta_2=273/473`=0.577


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