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The efficiency of carnot engine working between temperatures 200^@ C and 0^@ C is eta_1. The efficiency of this engine is eta_2 when it work between temperatures 0^@ C and -200^@ C. Then eta_1/eta_2=_____ |
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Answer» `1.0` `T_2`=0+273=273 K `T._1`=0+273 =273 K `T._2`=-200+273 =73 K `eta_1=200/473` `eta_2=200/273` `therefore eta_1/eta_2=273/473`=0.577 |
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