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The efficiency of carnot engine working between temperatures 200^@ C and 0^@ C is eta_1. The efficiency of this engine is eta_2 when it work between temperatures 0^@ C and -200^@ C. Then eta_1/eta_2=_____

Answer» <html><body><p>`1.0`<br/>`0.721`<br/>`0.577`<br/>`0.34`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`T_1`=200+<a href="https://interviewquestions.tuteehub.com/tag/273-1832932" style="font-weight:bold;" target="_blank" title="Click to know more about 273">273</a> =473 <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a><br/> `T_2`=0+273=273 K <br/> `T._1`=0+273 =273 K <br/> `T._2`=-200+273 =<a href="https://interviewquestions.tuteehub.com/tag/73-334616" style="font-weight:bold;" target="_blank" title="Click to know more about 73">73</a> K <br/> `eta_1=200/473` <br/> `eta_2=200/273`<br/> `therefore eta_1/eta_2=273/473`=0.577</body></html>


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