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The ejection of the photoelectron from the silver metal in the photoelectric effect exeriment can be stopped by applying the voltage of `0.35 V` when the radiation `256.7 nm` is used. Calculate the work function for silver metal.A. `4.45 eV`B. `7.86 eV`C. `5.36 eV`D. `6.78 eV` |
Answer» Correct Answer - A According to the phoeoelectric effect equation, `hv = hv_(0) +KE_("max")` `:. Hv_(0) (work function) = hv - KE_("max")` Find the energy of photon `(hv)` through wavelength: `hv = (hc)/(lambda) =((6.6 xx10^(-34)Js)(3.0xx10^(8)ms^(-1)))/(256.7xx10^(-9)m)` `= 0.077xx10^(-17)J = 7.7 xx 10^(-19) J` `= (7.7xx10^(-19)J) ((1eV)/(1.6xx10^(-19)J))` `= 4.8 eV` Find the maximum kinetic enegry through stopping potential: `KE_(max) = eV_(0) = 0.35eV` `:.` Work function `= (4.8eV) - (0.35eV)` `= 4.45 eV` |
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