InterviewSolution
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InterviewSolution
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The elastic collision between two bodies, A and B, can be cosidered using the following model. A and B are free to move along a common line without friction. When their distance is greater than `d = 1 m`, the interacting force is zero , when their distance is less d, a constant repulsive force `F = 6 N` is present. The mass of body A is `m_(A) = 1 kg` and it is initially at rest, the mass of body B is `m_(B) = 3 kg` and it is approaching body A head-on with a speed `v_(0) = 2 m//s`. Find th eminimum distance between A and B :- A. `0.25 m`B. `0.50 m`C. `0.75 m`D. `1 m` |
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Answer» Correct Answer - C `F_(ext) = 0` on system containing A & B `vec(P)` is conserved At minimum seperation both will move with same velocity `P_(1) = P_(f)` `2 xx 3 = 3 xx v` `v = (3)/(2)` `W_(all) = DeltaKE` `W_(F) = DeltaKE` `-6x = (1)/(2) xx 3 xx 2^(2) - (1)/(2) xx 4 xx ((3)/(2))^(2)` `x = 0.25` Minimum separation `= d - x = 1 - 0.25 = 0.75` |
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