The elastic limit of a steel cable is `3.0xx10^(8) N//m^(2)` and the cross-section area is `4 cm^(2)`. Find the maximum upward acceleration that can be given to a `900 kg` elevator supported by the cable if the stress is not to exceed one - third of the elastic limit.

The elastic limit of a steel cable is `3.0xx10^(8) N//m^(2)` and the c

1.	The elastic limit of a steel cable is `3.0xx10^(8) N//m^(2)` and the cross-section area is `4 cm^(2)`. Find the maximum upward acceleration that can be given to a `900 kg` elevator supported by the cable if the stress is not to exceed one - third of the elastic limit.
Answer» Correct Answer - B::C::D `(m(g+a))/A = 1/3sigma_(max)` `:. a = (sigma_(max)A)/(3 m) -g` `= ((3xx10^(8))(4xx10^(-4)))/(3xx900)-9.8` ` = 34.64 m//s^(2)`

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The elastic limit of a steel cable is `3.0xx10^(8) N//m^(2)` and the cross-section area is `4 cm^(2)`. Find the maximum upward acceleration that can be given to a `900 kg` elevator supported by the cable if the stress is not to exceed one - third of the elastic limit.

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