The elastic potential energy of a stretched wire is given byA. `U=(AL)/(2Y)l^(2)`B. `U=(AY)/(2L)l^(2)`C. `U=(1)/(2)((All)/(Y))l`D. `U=(1)/(2)*(YL)/(2A)*l`

The elastic potential energy of a stretched wire is given byA. `U=(AL)

1.	The elastic potential energy of a stretched wire is given byA. `U=(AL)/(2Y)l^(2)`B. `U=(AY)/(2L)l^(2)`C. `U=(1)/(2)((All)/(Y))l`D. `U=(1)/(2)(YL)/(2A)l`
Answer» Correct Answer - B (b) Elastic potential energy of a stretched wire is given by `E=(1)/(2)xx "stress" xx "strain" xx "volume" =(1)/(2)xx(F)/(A)xx(l)/(L)xxAL` `=(1)/(2)xxYxx"strain"xx "strain"xxAL=(1)/(2)xxYxx((l)/(L))^(2)xxAL` `therefore E=(Ayl^(2))/(2L)`

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The elastic potential energy of a stretched wire is given byA. `U=(AL)/(2Y)l^(2)`B. `U=(AY)/(2L)l^(2)`C. `U=(1)/(2)((All)/(Y))l`D. `U=(1)/(2)*(YL)/(2A)*l`

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The elastic potential energy of a stretched wire is given byA. `U=(AL)/(2Y)l^(2)`B. `U=(AY)/(2L)l^(2)`C. `U=(1)/(2)((All)/(Y))l`D. `U=(1)/(2)(YL)/(2A)l`