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The electric field associated with an electromagnetic wave in vacuum is given by `vecE=40cos(kz-6xx10^(8)t)hati,` where E, z and t are in volt per meter, meter and second respectively. The value of wave vector k isA. 2 `m^(-1)`B. `0.5m^(-1)`C. `6m^(-1)`D. `3m^(-1)` |
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Answer» Correct Answer - A Compare the given equation with `E=E_(0)cos(kz-omegat)` We get, `omega=6xx10^(8)s^(-1)` `therefore" Wave vector, k"=(omega)/(c)=(6xx10^(8)s^(-1))/(3xx10^(8)"m s"^(-1))=2m^(-1)` |
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