The electric field at a point due to a point charge is `20 NC^(-1)` and electric potential at that point is `10 JC^(-1)`. Calculate the distance of the point from the charge and the magnitude of the charge.A. 2500 VB. 22500 VC. 2000 VD. 20500 V

The electric field at a point due to a point charge is `20 NC^(-1)` an

1.	The electric field at a point due to a point charge is `20 NC^(-1)` and electric potential at that point is `10 JC^(-1)`. Calculate the distance of the point from the charge and the magnitude of the charge.A. 2500 VB. 22500 VC. 2000 VD. 20500 V
Answer» Correct Answer - B `V=1/(4piin_(0))xxq/r=(9xx10^(9)xx25xx10^(-6))/10` = 22500 V

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The electric field at a point due to a point charge is `20 NC^(-1)` and electric potential at that point is `10 JC^(-1)`. Calculate the distance of the point from the charge and the magnitude of the charge.A. 2500 VB. 22500 VC. 2000 VD. 20500 V

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