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The electric field E due to any point charge near it is defined as E = \(\lim\limits_{q\to 0}\cfrac{F}{q}\) where q is the test charge and F is the force acting on it. What is the physical significance of \(\lim\limits_{q\to 0}\) in this expression ?Draw the electric lines of point charge Q when(i) Q > 0 and (ii) Q < 0. |
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Answer» The physical significance of \(\lim\limits_{q\to 0}\) in the definition of electric field E = \(\lim\limits_{q\to 0}\cfrac{F}{q}\) The point test charge q produces its own electric field, hence it will modify the electric field strength to be measured. Therefore, the test charge used to measure the electric field must be too small. The electric lines of force are shown in figure above. |
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