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The electric field in a region is given by `E = 3/5 E_0hati +4/5E_0j` with `E_0 = 2.0 x 10^3 N//C`. Find the flux of this field through a rectangular surface of area `0.2 m^2` parallel to the y-z plane. |
Answer» `phi_(E)=vec(E).vec(S)=(3/5 E_(0) hat(i)+4/5 E_(0) hat(j)).(0.2 hat(i))=240 (N-m^(2))/C` | |