1.

The electric field inside a parallel plate capacitor is E. Find the amount of work done in moving a charge q over a closed rectangular loop abcda.

Answer»

Work done in moving a charge q from a to b = 0 

Work done in moving a charge q from c to d = 0 

This is because the electric field is perpendicular to the displacement. 

Now, work done from b to c = – work done from d to a 

Therefore, total work done in moving a charge q over a closed loop = 0.



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