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The electric field inside a parallel plate capacitor is E. Find the amount of work done in moving a charge q over a closed rectangular loop abcda? |
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Answer» Work done in moving a charge q on path abcda is : \(= q\vec E.(\vec{ab})+q\vec E.(\vec{bc})+q\vec E.(\vec{cd})+q\vec E.(\vec{da})\) = qE(ab) cos90˚+ qE (bc) cos0˚ + qE(cd) cos90˚ + qE (da) cos180˚ = qE(bc) – qE(da) = 0 [since, bc = da]. |
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