The electric field intensity due to a thin infinity long straight wire of uniform linear charge density `lambda` at O is- A. `(lambda)/(2pi epsilon_(0)R)`B. `(lambda sqrt(2))/(2pi epsilon_(0)R)`C. `(lambda sqrt(5))/(2pi epsilon_(0)R)`D. zero

The electric field intensity due to a thin infinity long straight wire

1.	The electric field intensity due to a thin infinity long straight wire of uniform linear charge density `lambda` at O is- A. `(lambda)/(2pi epsilon_(0)R)`B. `(lambda sqrt(2))/(2pi epsilon_(0)R)`C. `(lambda sqrt(5))/(2pi epsilon_(0)R)`D. zero
Answer» Correct Answer - A `E_(arc) = (2k lambda)/(r) sin.(theta)/(2)` `=(2k lambda)/(r) sin.(180^(@))/(2)` `= (lambda)/(2pi epsilon_(0)R)`

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The electric field intensity due to a thin infinity long straight wire of uniform linear charge density `lambda` at O is- A. `(lambda)/(2pi epsilon_(0)R)`B. `(lambda sqrt(2))/(2pi epsilon_(0)R)`C. `(lambda sqrt(5))/(2pi epsilon_(0)R)`D. zero

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