The electric fields of two plane electromagnetic plane waves, in vacuum, are given by,−→E1=E0^j cos(ωt−kx) and, −→E2=E0^k cos(ωt−ky).At t=0, a particle of charge q is at origin with a velocity →v=(0.8 c)^j (Here, c is the speed of light in vacuum). The instantaneous force experienced by the particle is:

The electric fields of two plane electromagnetic plane waves, in vacuu

1.	The electric fields of two plane electromagnetic plane waves, in vacuum, are given by,−→E1=E0^j cos(ωt−kx) and, −→E2=E0^k cos(ωt−ky).At t=0, a particle of charge q is at origin with a velocity →v=(0.8 c)^j (Here, c is the speed of light in vacuum). The instantaneous force experienced by the particle is:
Answer» The electric fields of two plane electromagnetic plane waves, in vacuum, are given by, $_{1} = E_{0}^j cos (ω t - k x)$ and, $_{2} = E_{0}^k cos (ω t - k y)$ . At $t = 0$ , a particle of charge $q$ is at origin with a velocity $\to v = (0.8 c)^j$ (Here, $c$ is the speed of light in vacuum). The instantaneous force experienced by the particle is:

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