The electric force between two electric charges is given by F= (1)/(4pi epsi_(0))(q_(1)q_(2))/(r^(2)). where is a distance . between charges q_(1) and q_(2) . So, unit and dimensional formula of epsi_(0), is ...... and...... respectively.

The electric force between two electric charges is given by F= (1)/(4p

1.	The electric force between two electric charges is given by F= (1)/(4pi epsi_(0))(q_(1)q_(2))/(r^(2)). where is a distance . between charges q_(1) and q_(2) . So, unit and dimensional formula of epsi_(0), is ...... and...... respectively.
Answer» `N^(1)C^(2)m^(-2),M^(-1)L^(-3)T^(4)A^(2)` `N^(-1)CM^(-2),M^(-1)L^(-1)T^(-1)A` `N^(2)C^(2)m^(-2)M^(-1)L^(-3)T^(4)A^(2)` `NCm^(-2),MLTA` SOLUTION :`F=(1)/(4PI epsi_(0)).(q_(1)q_(2))/(r^(2))` `:.epsi_(0)=(q_(1)q_(2))/(4pi Fr^(2))` `:.` Units of `epsi_(0)=(C^(2))/(Nm^(2))=N^(-1)C^(2)m^(-2)` `[epsi_(0)]=([C^(2)])/([N][m^(2)])=(A^(2)T^(2))/((M^(1)L^(1)T^(-2))(L^(2)))` `=M^(-1)L^(-3)T^(4)A^(2)`