1.

the electric lamp whose resistance is 40 ohms and conductor of 8 ohms resistance are connected in series to 12 volt battery in an electric circuit calculate the total resistance of the circuit and the current flowing through the circuit

Answer»

Total resistance = Resistance of lamp + Resistance of conductor = (40+8) = 48 Ω

We know that :

V = IR
(V = Voltage , I = Current , R = Resistance)

By, putting the available values, in the above-mentioned mathematical equation, we get :

12 = I × 48

I = 12/48

I = 0.25 A



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