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    				| 1. | The electric potential at a point in free space due to a charge `Q` coulomb is `Q xx 10^(11)` volts. The electric field at that point isA. `12piepsi_(0)Qxx10^(22)Vm^(-1)`B. `4 pi epsi_(0)Qxx10^(22)Vm^(-1)`C. `12pi epsi_(0)Qxx10^(20)V m^(-1)`D. `4 pi epsi _(0)Qxx10^(20)V m^(-1)` | 
| Answer» Correct Answer - B Here, `V=Q/(4piepsilon_0r) =Qxx10^11` `therefore 4piepsilon_0r=10^(-11)` …(i) Now, `E=Q/(4piepsilon_0r^2)=(Qxx4piepsilon_0)/((4piepsilon_0r)^2)=(4piepsilon_0Q)/((10^(-11))^2` (Using (i)) `=4piepsilon_0Qxx10^22 V m^(-1)` | |