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The electric potential decreases uniformly from `100 V` to `50 V` as one moves along the x-axis from `x = 0` to `x = 5 m`. The electric field at `x = 2 m` must be equal to `10 V//m`. Is this statement true or false. |
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Answer» `(delV)/(delx)=(-50)/5=-10V//m` Now `|E|=sqrt(((delV)/(delx))^2+((delV)/(dely))^2+((delV)/(delz))^2)` now information is given about `(delV)/(dely) and (delV)/(delz)`. Hence ` `|E|ge|(delV)/(delx)| or |E|ge10V/m` |
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