InterviewSolution
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InterviewSolution
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The electrochemical cell shows below is a concentration cell. `M|M^(2+)` (saturated solution of a sparingly soluble salt, `MX_(2))||M^(2+)(0.001)" mol "dm^(-3))|M`. The emf of the cell Depends on the difference in concentration of `M^(2+)` ions at the two electrodes. the emf of the cell at 298K is 0.059V. Q. The solubility product `(K_(sp),mol^(3)dm^(-9))` of `MX_(2)` at 298K based on the information available for the given concentration cell is (take `2.303xxRxx298//F=0.059V`)A. `1xx10^(-15)`B. `5.7`C. `1xx10^(-12)`D. `4xx10^(-12)` |
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Answer» Correct Answer - B `M|M^(2+)underset(0.001M)((aq)||M^(2+))(aq)|M` Anode: `MtoM^(2+)(aq)+2e^(-)` Cathode: `underline(M^(2+)(aq)+2e^(-)toM" ")` `M^(2+)(aq)hArrM^(2+)(aq)` `E_(cell)=0-(0.059)/(2)"log"((M^(2+)(aq))/(10^(-3)))` `0.059=-(0.059)/(2)"log"((M^(2+)(aq))/(10^(-3)))implies-2="log"((M^(2+)(aq))/(10^(-3)))` `10^(-2)xx10^(-3)=M^(2+)(aq)="solubility"=s` `K_(sp)=4S^(3)=4xx(10^(-5))^(3)=4xx10^(-15)`. |
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