The electrode potentials for `Cu^(2+)+e^(-)toCu^(+)` and `Cu^(+)e^(-)toCu_(s)` are `+0.15`V and `+0.50V` respectively the value of `E_((Cu^(2+))/(Cu))^(@)` will be?A. 0.650VB. 0.150VC. 0.500VD. 0.325V

The electrode potentials for `Cu^(2+)+e^(-)toCu^(+)` and `Cu^(+)e^(-)t

1.	The electrode potentials for `Cu^(2+)+e^(-)toCu^(+)` and `Cu^(+)e^(-)toCu_(s)` are `+0.15`V and `+0.50V` respectively the value of `E_((Cu^(2+))/(Cu))^(@)` will be?A. 0.650VB. 0.150VC. 0.500VD. 0.325V
Answer» Correct Answer - D `Cu^(2+)(aq)+ e^(-)rarrCu^(+)(aq):E_(1)^(@)=0.15V` `DeltaG_(1)^(@)=-nE_(2)^(@)F=-0.15F` `Cu^(+)(aq)+e^(-)rarrCu(s):E_(2)^(@)=0.50V` `DeltaG_(2)^(@)=-nE_(2)^(@)F=-0.50F` `Cu^(2+)(aq)+2e^(-)rarrCu(s):E_(3)^(@)= ?` `DeltaG_(3)^(@)=-nE_(3)^(@)F= -2E_(3)^(@)F` `DeltaG_(3)^(@)=DeltaG_(1)^(@)+DeltaG_(2)^(@)` `-2E_(3)^(@)F=-0.15F=0.50F` `therefore E_(3)^(@)=(0.65)/(2)=0.325V`

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The electrode potentials for `Cu^(2+)+e^(-)toCu^(+)` and `Cu^(+)e^(-)toCu_(s)` are `+0.15`V and `+0.50V` respectively the value of `E_((Cu^(2+))/(Cu))^(@)` will be?A. 0.650VB. 0.150VC. 0.500VD. 0.325V

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